Android判断是否Root方法介绍

为了照顾那些着急的同学，先直接给出结论：

    private static final String[] rootRelatedDirs = new String[]{
            "/su", "/su/bin/su", "/sbin/su",
            "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su", 
            "/system/xbin/su",
            "/system/bin/su", "/system/sd/xbin/su", "/system/bin/failsafe/su",
            "/system/bin/cufsdosck", "/system/xbin/cufsdosck", "/system/bin/cufsmgr",
            "/system/xbin/cufsmgr", "/system/bin/cufaevdd", "/system/xbin/cufaevdd",
            "/system/bin/conbb", "/system/xbin/conbb"};
 
    public static boolean hasRootPrivilege() {
        boolean hasRootDir = false;
        String[] rootDirs;
        int dirCount = (rootDirs = rootRelatedDirs).length;
        for (int i = 0; i < dirCount; ++i) {
            String dir = rootDirs[i];
            if ((new File(dir)).exists()) {
                hasRootDir = true;
                break;
            }
        }
        return Build.TAGS != null && Build.TAGS.contains("test-keys") || hasRootDir;
    }

好，接下来我们来看看到底是如何得到上述的解决方案的。首先，这是既有的判断root权限的方案，即判定两个root权限相关文件夹是否存在，以及当前账户是否具备访问其内容的权限，如果都成立，那么就认为当前账号具备root权限。然而，这种root方案在一些情况下不能很好地发挥作用。

/**
 * 判断Android设备是否拥有Root权限
 */
public class RootCheck {
 
    private final static String TAG = "RootUtil";
 
    public static boolean isRoot() {
        String binPath = "/system/bin/su";
        String xBinPath = "/system/xbin/su";
        if (new File(binPath).exists() && isExecutable(binPath))
            return true;
        if (new File(xBinPath).exists() && isExecutable(xBinPath))
            return true;
        return false;
    }
 
    private static boolean isExecutable(String filePath) {
        Process p = null;
        try {
            p = Runtime.getRuntime().exec("ls -l " + filePath);
            // 获取返回内容
            BufferedReader in = new BufferedReader(new InputStreamReader(p.getInputStream()));
            String str = in.readLine();
            Log.i(TAG, str);
            if (str != null && str.length() >= 4) {
                char flag = str.charAt(3);
                if (flag == 's' || flag == 'x')
                    return true;
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (p != null) {
                p.destroy();
            }
        }
        return false;
    }
}

然后我就找到了如下方案，该方案号称是腾讯bugly的root权限判断方案：

private static final String[] a = new String[]{"/su", "/su/bin/su", "/sbin/su",
    "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su", 
    "/system/xbin/su", "/system/bin/su", "/system/sd/xbin/su",
    "/system/bin/failsafe/su", "/system/bin/cufsdosck", 
    "/system/xbin/cufsdosck", "/system/bin/cufsmgr", 
    "/system/xbin/cufsmgr", "/system/bin/cufaevdd", 
    "/system/xbin/cufaevdd", "/system/bin/conbb", 
    "/system/xbin/conbb"};
 
public static boolean p() {
  boolean var0 = false;
  String[] var1 = a;
  int var2 = a.length;
 
  for(int var3 = 0; var3 < var2; ++var3) {
    String var4 = var1[var3];
    if ((new File(var4)).exists()) {
      var0 = true;
      break;
    }
  }
 
  return Build.TAGS != null && Build.TAGS.contains("test-keys") || var0;
}

当然，本人生性多疑，偶像是曹操曹丞相，所以自然不能人云亦云，还是实际确认一下bugly实际上是否是这样实现的，以及确保bugly在新的版本中有没有对该方案有进一步的改进。

然后我就到bugly官网，下载了其最新发布的jar包，笔者下载时最新的版本为4.4.4，然后直接解压，然后在解压的目录中搜索“test-keys”内容。

grep -r test-keys "D:\迅雷下载\Bugly_v3.4.4

最后找到了对应的文件位置和对应方法：com\tencent\bugly\crashreport\common\info\b.class

private static final String[] a = new String[]{"/su", "/su/bin/su",
 "/sbin/su", "/data/local/xbin/su", "/data/local/bin/su", 
"/data/local/su", "/system/xbin/su", "/system/bin/su", 
"/system/sd/xbin/su", "/system/bin/failsafe/su",
 "/system/bin/cufsdosck", "/system/xbin/cufsdosck",
 "/system/bin/cufsmgr", "/system/xbin/cufsmgr",
 "/system/bin/cufaevdd", "/system/xbin/cufaevdd",
 "/system/bin/conbb", "/system/xbin/conbb"};
public static boolean l() {
    boolean var0 = false;
    String[] var1;
    int var2 = (var1 = a).length;
 
    for(int var3 = 0; var3 < var2; ++var3) {
        String var4 = var1[var3];
        if ((new File(var4)).exists()) {
            var0 = true;
            break;
        }
    }
 
    return Build.TAGS != null && Build.TAGS.contains("test-keys") || var0;
}

然后分析一下对应变量的意思，我们就能还原出腾讯判断Root的代码，即我们开头所贴出的解决方案：

    private static final String[] rootRelatedDirs = new String[]{
            "/su", "/su/bin/su", "/sbin/su",
            "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su", 
            "/system/xbin/su",
            "/system/bin/su", "/system/sd/xbin/su", "/system/bin/failsafe/su",
            "/system/bin/cufsdosck", "/system/xbin/cufsdosck", "/system/bin/cufsmgr",
            "/system/xbin/cufsmgr", "/system/bin/cufaevdd", "/system/xbin/cufaevdd",
            "/system/bin/conbb", "/system/xbin/conbb"};
 
    public static boolean hasRootPrivilege() {
        boolean hasRootDir = false;
        String[] rootDirs;
        int dirCount = (rootDirs = rootRelatedDirs).length;
        for (int i = 0; i < dirCount; ++i) {
            String dir = rootDirs[i];
            if ((new File(dir)).exists()) {
                hasRootDir = true;
                break;
            }
        }
        return Build.TAGS != null && Build.TAGS.contains("test-keys") || hasRootDir;
    }

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原文出处：https://blog.csdn.net/qq_31433709/article/details/122568359